Practice Questions for CSIR NET Complex Analysis : Power Series and ROC V

Practice Questions for NET JRF Complex Analysis Assignment: Power Series and ROC

56. Expansion of function \(f(z)=\frac{1}{(3-2 z)}\) in power of \((z-3)\) and the radius of convergence of the series so obtained are





57. For the function \(f(z)=\frac{z-\sin z}{z^{3}}\), the point \(z=0\) is





58. The singularity of \(e^{\sin z}\) at \(z=\infty\) is





59. Let \(p(z)=a_{0}+a_{1} z+\ldots+a_{n} z^{n}\) and \(q(z)=b_{1} z+b_{2} z^{2}+\ldots+b_{n} z^{n}\) be complex polynomials. If \(a_{0}, b_{1}\) are non-zero complex numbers then the residue of \(\frac{p(z)}{q(z)}\) at 0 is equal to





60. The function \(\frac{1}{z(z-1)^{3}}\) has a pole of order \(p\) and residues \(r\) where





61. Residue of \(\frac{\sin z}{z^{4}}\) at its singularity is





62. The residue of \(e^{1 / z}\) at \(z=0\) is





63. Let \(f: \mathbb{C} \rightarrow \mathbb{C}\) be analytic for a simple pole at \(z=0\) and let \(g: \mathbb{C} \rightarrow \mathbb{C}\) be analytic. Then, the value of \(\frac{\operatorname{Res}_{z=0}\{f(z) g(z)\}}{\operatorname{Res}_{z=0} f(z)}\) is





64. Let \(f(z)=\frac{z}{8-z^{3}}, z=x+i y\) then \(\operatorname{Res}_{z=2} f(z)\) is





65. The sum of the residues at all the poles of \(f(z)=\frac{\cot \pi z}{(z+a)^{2}}\), where \(a\) is constant \((a \neq 0, \pm 1, \pm 2, \ldots)\) is





66. \(\int_{0}^{2 \pi} \frac{d \theta}{13-5 \sin \theta}\) is equals





67. The residue of \(\frac{\sin z}{z^{8}}\) at \(z=0\) is





68. Let \(P(z), Q(z)\) be two complex nonconstant polynomials of degree \(m, \(n\) respectively. The number of roots of \(H(z)=P(z) Q(z)\) counted with multiplicity is equal to:





69. The residue of function \(f(z)=e^{-e^{1 / z}}\) at \(z=0\) is:





70. Let \(D\) be the open unit disc in \(\mathbb{C}\) and \(H(D)\) be the collection of all holomorphic functions on it. Let

\(S=\left\{f \in H(D): f\left(\frac{1}{2}\right)=\frac{1}{2}, f\left(\frac{1}{4}\right), \ldots, f\left(\frac{1}{2 n}\right), \ldots\right\}\)

\(T=\left\{f \in H(D): f\left(\frac{1}{2}\right)=f\left(\frac{1}{3}\right)=\frac{1}{2}, f\left(\frac{1}{4}\right)=f\left(\frac{1}{5}\right), \ldots, f\left(\frac{1}{2 n}\right)=f\left(\frac{1}{2 n+1}\right), \ldots\right\}\)

Then





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